2026/04/11

[LeetCode] 102 Binary Tree Level Order Traversal

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode() : val(0), left(nullptr), right(nullptr) {}
 *     TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
 *     TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
 * };
 */
class Solution {
private:
  std::queue<TreeNode*> Q;
  std::unordered_map<TreeNode*, int> levelMap;
  vector<vector<int>> ans;
  void addIntoAns(TreeNode* node) {
    if (!node)
      return;
    int level = levelMap[node];
    if (ans.size() < level) {
      ans.resize(level);
    }
    ans[level - 1].push_back(node->val);
  }

  void expand(TreeNode* node) {
    if (!node)
      return;
    if (node->left) {
      Q.push(node->left);
      levelMap[node->left] = levelMap[node] + 1;
    }
    if (node->right) {
      Q.push(node->right);
      levelMap[node->right] = levelMap[node] + 1;
    }
  }

public:
  vector<vector<int>> levelOrder(TreeNode* root) {
    Q.push(root);
    levelMap[root] = 1;
    while(!Q.empty()) {
      TreeNode* cur = Q.front();
      Q.pop();
      addIntoAns(cur);
      expand(cur); 
    }
    return ans;
  }
};