2026/04/18

[LeetCode] 105 Construct Binary Tree from Preorder and Inorder Traversal

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/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode() : val(0), left(nullptr), right(nullptr) {}
 *     TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
 *     TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
 * };
 */
class Solution {
public:
  TreeNode* buildTreeImpl(int preStart, int inStart, int inEnd,
                          vector<int>& preorder, 
                          vector<int>& inorder,
                          std::unordered_map<int, int>& inOrderMap) {
    if (inStart > inEnd)
      return nullptr;

    int nodeVal = preorder[preStart];
    TreeNode* node = new TreeNode(nodeVal);
    int inMidIdx = inOrderMap[nodeVal];
    int leftSize = inMidIdx - inStart;
    node->left = buildTreeImpl(preStart + 1, inStart, inMidIdx - 1,
                               preorder, inorder, inOrderMap);
    node->right = buildTreeImpl(preStart + 1 + leftSize, inMidIdx + 1, inEnd,
                               preorder, inorder, inOrderMap);
    return node;
  }

  TreeNode* buildTree(vector<int>& preorder, vector<int>& inorder) {
    std::unordered_map<int, int> inOrderMap;
    for (int i = 0; i < inorder.size(); i++)
      inOrderMap[inorder[i]] = i;
    return buildTreeImpl(0, 0, inorder.size() - 1, preorder, inorder, inOrderMap);
  }
};